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The s.d. of the sampling distribution of sample mean for the population with s.d. 0.5, population size 122  and sample size 22 is

Question

The s.d. of the sampling distribution of sample mean for the population with s.d. 0.5, population size 122  and sample size 22 is

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Solution 1

The standard deviation of the sampling distribution of the sample mean, also known as the standard error, can be calculated using the formula:

Standard Error = σ / sqrt(n)

where σ is the standard deviation of the population and n is the sample size.

Given in the problem, we have σ = 0.5 (population standard deviation) and n = 22 (sample size).

Substituting these values into the formula, we get:

Standard Error = 0.5 / sqrt(22)

Now, calculate the square root of 22 and divide 0.5 by the result to get the standard error.

This problem has been solved

Solution 2

The standard deviation of the sampling distribution of the sample mean, also known as the standard error, can be calculated using the formula:

Standard Error (SE) = σ / sqrt(n)

where: σ = standard deviation of the population n = size of the sample

Given in the problem: σ = 0.5 (standard deviation of the population) n = 22 (size of the sample)

Substituting these values into the formula gives:

SE = 0.5 / sqrt(22)

Now, calculate the square root of 22 and divide 0.5 by the result to get the standard error.

This problem has been solved

Solution 3

The standard deviation of the sampling distribution of the sample mean, also known as the standard error, can be calculated using the formula:

Standard Error (SE) = σ / sqrt(n)

where: σ = population standard deviation n = sample size

Given in the problem, we have: σ = 0.5 (population standard deviation) n = 22 (sample size)

Substituting these values into the formula, we get:

SE = 0.5 / sqrt(22)

Now, calculate the square root of 22 and divide 0.5 by the result to get the standard error.

This problem has been solved

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