When 40 kJ of energy is transferred to a quantity of a liquid substance, its temperatureincreases by 20 K. When 600 kJ of energy is transferred to the same quantity of the liquid atits boiling temperature, it vaporizes completely at constant temperature. What isspecific latent heat of vaporizationspecific heat capacity of the liiquid
Question
When 40 kJ of energy is transferred to a quantity of a liquid substance, its temperatureincreases by 20 K. When 600 kJ of energy is transferred to the same quantity of the liquid atits boiling temperature, it vaporizes completely at constant temperature. What isspecific latent heat of vaporizationspecific heat capacity of the liiquid
Solution
To solve this problem, we need to use the formulas for specific heat capacity and latent heat of vaporization.
- Specific Heat Capacity (c): The formula is Q = mcΔT, where Q is the heat energy transferred, m is the mass of the substance, c is the specific heat capacity, and ΔT is the change in temperature.
From the problem, we know that Q = 40 kJ = 40000 J (since 1 kJ = 1000 J), and ΔT = 20 K. We don't know the mass (m), but we can express c in terms of m:
c = Q / (mΔT) = 40000 J / (m * 20 K)
- Specific Latent Heat of Vaporization (L): The formula is Q = mL, where Q is the heat energy transferred, m is the mass of the substance, and L is the specific latent heat of vaporization.
From the problem, we know that Q = 600 kJ = 600000 J. Again, we don't know the mass (m), but we can express L in terms of m:
L = Q / m = 600000 J / m
So, the specific heat capacity of the liquid is 40000 J / (m * 20 K) and the specific latent heat of vaporization is 600000 J / m.
Without the mass of the liquid, we can't calculate numerical values for these quantities. However, if we knew the mass, we could substitute it into these expressions to find the specific heat capacity and latent heat of vaporization.
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