A trader bought an article and then sold. Had he bought at 10% less and sold at 10% more, he would have doubled his profit percentage.What was the original profit percentage?

Let's solve this step by step:

Step 1: Let's assume the cost price of the article is $100. So, the selling price that gives the trader his original profit is$100 + $P$ (where P is the original profit percentage).

Step 2: According to the problem, if the trader had bought the article at 10% less, the cost price would be $90.

Step 3: And if he sold it at 10% more, the selling price would be $110 +$P$.

Step 4: The problem states that this would have doubled his profit. So, the profit in this case would be $2P$.

Step 5: We can set up the equation from the information above: $90 + 2P = 110 + P$.

Step 6: Solving this equation gives us $P = 20$.

So, the original profit percentage was 20%.

Let's solve this step by step:

Step 1: Let's assume the cost price of the article is $100. So, the selling price that gives the original profit can be assumed as$100 + $x.

Step 2: According to the problem, if the trader had bought the article at 10% less, the cost price would be $90. And if he sold it at 10$110 + $x.

Step 3: The problem states that this would have doubled his profit percentage. So, the profit in this case would be 2 * original profit.

Step 4: We can set up the equation as follows: (110 + x - 90) = 2 * (100 + x - 100)

Step 5: Simplifying the equation gives: 20 + x = 2x

Step 6: Solving for x gives: x = 20

So, the original profit percentage was 20%.