How many moles are there in 22.816 g of CaCO3?Give your answer in moles and to three decimal places.(Molar mass of CaCO3 = 100.07 g mol-1)
Question
How many moles are there in 22.816 g of CaCO3?Give your answer in moles and to three decimal places.(Molar mass of CaCO3 = 100.07 g mol-1)
Solution
To calculate the number of moles in a given mass of a substance, you can use the formula:
Number of moles = mass of substance / molar mass of substance
Given: Mass of CaCO3 = 22.816 g Molar mass of CaCO3 = 100.07 g/mol
Substitute the given values into the formula:
Number of moles = 22.816 g / 100.07 g/mol = 0.228 moles
So, there are 0.228 moles in 22.816 g of CaCO3.
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