The equation of a circle in a coordinate plane is given by the formula (x-h)² + (y-k)² = r², where (h, k) is the center of the circle and r is the radius.

Given that the center of the circle is (-2, 3) and the radius is 4, we can substitute these values into the formula to get the equation of the circle.

So, the equation of the circle is:

(x - (-2))² + (y - 3)² = 4²

Simplifying this gives:

(x + 2)² + (y - 3)² = 16

So, the equation of the circle with center (-2, 3) and radius 4 is (x + 2)² + (y - 3)² = 16.

Question

The equation of a circle in a coordinate plane is given by the formula (x-h)² + (y-k)² = r², where (h, k) is the center of the circle and r is the radius.

Given that the center of the circle is (-2, 3) and the radius is 4, we can substitute these values into the formula to get the equation of the circle.

So, the equation of the circle is:

(x - (-2))² + (y - 3)² = 4²

Simplifying this gives:

(x + 2)² + (y - 3)² = 16

So, the equation of the circle with center (-2, 3) and radius 4 is (x + 2)² + (y - 3)² = 16.

Knowee AI · Accepted Answer

The equation of a circle in a coordinate plane is given by the formula (x-h)² + (y-k)² = r², where (h, k) is the center of the circle and r is the radius.

Given that the center of the circle is (-2, 3) and the radius is 4, we can substitute these values into the formula to get the equation of the circle.

So, the equation of the circle is:

(x - (-2))² + (y - 3)² = 4²

Simplifying this gives:

(x + 2)² + (y - 3)² = 16

So, the equation of the circle with center (-2, 3) and radius 4 is (x + 2)² + (y - 3)² = 16.

What is the equation of a circle with center (-2, 3) and radius 4?A.B.C.D.

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