Use volume by disk method to Determine the volume of the surface of revolution about1. 𝒙 = 𝟎2. 𝒚 = 𝟎3. 𝒙 = +𝒂

I'm sorry, but you didn't provide a specific function to revolve around the axes or the line x = a. The volume of a solid of revolution can be found using the disk method, which involves integrating the cross-sectional area of the solid along the axis of rotation.

Here's a general step-by-step guide on how to use the disk method:

1. Identify the function you're revolving. This could be a simple function like y = x^2 or something more complex.

2. Determine the axis of rotation. This could be the x-axis (y = 0), the y-axis (x = 0), or some other line like x = a.

3. Set up an integral that represents the volume of the solid. The limits of integration will be the points where the function intersects the axis of rotation. The integrand will be π times the function squared, which represents the area of a cross-sectional disk.

4. Evaluate the integral to find the volume.

For example, if you're revolving y = x^2 around the x-axis from x = 0 to x = 1, the volume would be:

V = ∫ from 0 to 1 of π*(x^2)^2 dx = ∫ from 0 to 1 of πx^4 dx = [π/5]x^5 from 0 to 1 = π/5 units^3.

Please provide a specific function and axis of rotation for a more detailed solution.