According to Joule's Law of heating, heat produced in a resistance is H=I^2RT. if the errors in the measurement of I.R and t are 3% ,4% and 6% respectively then the error of measurement of H is
Question
According to Joule's Law of heating, heat produced in a resistance is H=I^2RT. if the errors in the measurement of I.R and t are 3% ,4% and 6% respectively then the error of measurement of H is
Solution
According to the rules of error propagation, when a quantity is calculated as a product or quotient of other quantities, the relative errors add up.
In this case, the heat H is calculated as a product of current I, resistance R, and time t. Therefore, the relative error in H is the sum of the relative errors in I, R, and t.
The relative error in I is 3%, in R is 4%, and in t is 6%.
Therefore, the relative error in H is 3% + 4% + 6% = 13%.
So, the error of measurement of H is 13%.
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