Let Sn=n∑k=1 (√1+kn2−1), then 20(limn→∞ Sn) is equal to
Question
Let Sn=n∑k=1 (√1+kn2−1), then 20(limn→∞ Sn) is equal to
Solution
The given expression is Sn = n∑k=1 (√1+kn2−1). We need to find the value of 20(limn→∞ Sn).
Step 1: Simplify the expression inside the square root
We can rewrite the expression inside the square root as 1 + k/n - 1, which simplifies to k/n.
Step 2: Simplify the expression
So, the expression becomes Sn = n∑k=1 √k/n.
Step 3: Recognize the form of the expression
This is the form of a Riemann sum for the integral from 0 to 1 of √x dx.
Step 4: Evaluate the integral
The integral of √x with respect to x from 0 to 1 is (2/3)x^(3/2) from 0 to 1, which equals 2/3.
Step 5: Take the limit as n approaches infinity
As n approaches infinity, Sn approaches 2/3.
Step 6: Multiply by 20
Finally, we multiply this limit by 20 to get 20(limn→∞ Sn) = 20 * 2/3 = 40/3.
So, 20(limn→∞ Sn) is equal to 40/3.
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