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Let Sn=n∑k=1 (√1+kn2−1), then 20(limn→∞  Sn) is equal to

Question

Let Sn=n∑k=1 (√1+kn2−1), then 20(limn→∞  Sn) is equal to

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Solution

The given expression is Sn = n∑k=1 (√1+kn2−1). We need to find the value of 20(limn→∞  Sn).

Step 1: Simplify the expression inside the square root

We can rewrite the expression inside the square root as 1 + k/n - 1, which simplifies to k/n.

Step 2: Simplify the expression

So, the expression becomes Sn = n∑k=1 √k/n.

Step 3: Recognize the form of the expression

This is the form of a Riemann sum for the integral from 0 to 1 of √x dx.

Step 4: Evaluate the integral

The integral of √x with respect to x from 0 to 1 is (2/3)x^(3/2) from 0 to 1, which equals 2/3.

Step 5: Take the limit as n approaches infinity

As n approaches infinity, Sn approaches 2/3.

Step 6: Multiply by 20

Finally, we multiply this limit by 20 to get 20(limn→∞  Sn) = 20 * 2/3 = 40/3.

So, 20(limn→∞  Sn) is equal to 40/3.

This problem has been solved

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