The density of sea water is 1.025 kg / m3 calculate the volume of the water which would be pumped into the dead sea every year. use density = mass / volume
Question
The density of sea water is 1.025 kg / m3 calculate the volume of the water which would be pumped into the dead sea every year. use density = mass / volume
Solution
To calculate the volume of water that would be pumped into the Dead Sea every year, we need to know the mass of the water being pumped. The question does not provide this information.
However, if we had the mass, we could use the formula for density, which is density = mass/volume. Rearranging this formula to solve for volume gives us volume = mass/density.
So, if we knew the mass of the water being pumped into the Dead Sea every year, we could divide that by the density of sea water (1.025 kg/m3) to find the volume.
Similar Questions
Calculate the amount that the pumped water would raise the level of the dead sea by every year assume that there is no loss of sea level by other means. use volume = surface area x length
Measurements have shown that the concentration of salt in seawater is 35.5·gL−1. Calculate the volume in liters of seawater that must be evaporated to recover 0.0500kg of salt.Round your answer to 3 significant digits.
The pressure at what depth in seawater (density 1,025 kg/m3) is equivalent to that at a depth of 10.0 m in fresh water (density 1,000 kg/m3)?
The earth has a mass of approximately kilograms . The volume of the earth's oceans is approximately cubic kilometers , and ocean water has a mass of about . To the nearest hundredth of a percent, what percent of the earth's mass is from the oceans?
The density of sea water is 1025 kg m^- 3. How many times is the pressure at the depth of 3 km under the sea surface greater than the atmospheric pressure? (g = 9.8 ms^-2 )
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.