A block–spring system vibrating on a frictionless, horizontal surface with an amplitude of 2.0 cm has an energy of 14 J. If the block is replaced by one whose mass is twice the mass of the original block and the amplitude of the motion is again 2.0 cm, what is the energy of the system?

A 1.13-kg mass attached to a spring is displaced 7.87 cm from the equilibrium position. It is released and then oscillates with a frequency of 4.05 Hz.  What is the energy of the motion when the mass passes through the equilibrium

A 1.00 x 10-2 kg block is resting on a horizontal frictionless surface and is attached to ahorizontal spring whose spring constant is 124 N/m. The block is shoved parallel to the springaxis and is given an initial speed of 8.00 m/s, while the spring is initially unstrained. What isthe amplitude of the resulting simple harmonic motion?

The motion of a block-spring system is described by x = A sin (ωt). Find ω knowing that the potential energy equals the kinetic energy for the first time at t = 2.00 s.

A 500 g block on a frictionless, horizontal surface is attached to a spring with constant k =8.7 N/m. A second block rests on the first, and the whole system executes simple harmonicmotion with period 1.8 s. When the amplitude of the motion is increased to 35 cm the upperblock just begins to slip. Determine the coefficient of static friction between the blocks

Two blocks with masses m1=1kg and m2=2 kg are connected by a spring constant k=24 Nm−1 and placed on a frictionless horizontal surface. The block m1 is imparted an initial velocity v0=12 cms −1 to the right, the amplitude of oscillation is