The negation of (P ∧ q) → r is   P ∧ q ∧ ¬ rGroup startsTrue or FalseTrue, unselectedFalse

If    p → ( ¬p ∨ q) is false, then the truth values of p and q are respectively T, F.Group startsTrue or FalseTrue, unselectedFalse, unselected

The proposition p↔q  is equivalent to (¬p ∨ q) ∧(¬q ∨ p)  Group startsTrue or FalseTrue, unselectedFalse

Not (A and B) is the same as Not A and Not B.Group startsTrue or FalseTrue, unselectedFalse, unselected

This statement: [(p → q)   ↔   (￢ p ∨ q) ] is tautologyGroup startsTrue or False

Number of  rows appear in the truth table for this compound proposition  (p ∧ r ∧ s) ∨  (r ∧ ¬ t) equal 8.Group startsTrue or FalseTrue, unselectedFalse