The hybridization scheme that allows the formation of at least one pi (p) bond is sp2.

Here's why:

1. In sp2 hybridization, one s orbital and two p orbitals in the valence shell of the atom mix to form three equivalent sp2 hybrid orbitals.

2. These sp2 hybrid orbitals form sigma bonds with other atoms.

3. The remaining unhybridized p orbital can overlap sideways with p orbitals from other atoms to form a pi bond.

So, sp2 hybridization allows the formation of at least one pi bond. The other hybridizations (sp3, dsp3, d2sp3) do not have an unhybridized p orbital available for pi bond formation.

Question

The hybridization scheme that allows the formation of at least one pi (p) bond is sp2.

Here's why:

1. In sp2 hybridization, one s orbital and two p orbitals in the valence shell of the atom mix to form three equivalent sp2 hybrid orbitals.

2. These sp2 hybrid orbitals form sigma bonds with other atoms.

3. The remaining unhybridized p orbital can overlap sideways with p orbitals from other atoms to form a pi bond.

So, sp2 hybridization allows the formation of at least one pi bond. The other hybridizations (sp3, dsp3, d2sp3) do not have an unhybridized p orbital available for pi bond formation.

Knowee AI · Accepted Answer

The hybridization scheme that allows the formation of at least one pi (p) bond is sp2.

Here's why:

1. In sp2 hybridization, one s orbital and two p orbitals in the valence shell of the atom mix to form three equivalent sp2 hybrid orbitals.

2. These sp2 hybrid orbitals form sigma bonds with other atoms.

3. The remaining unhybridized p orbital can overlap sideways with p orbitals from other atoms to form a pi bond.

So, sp2 hybridization allows the formation of at least one pi bond. The other hybridizations (sp3, dsp3, d2sp3) do not have an unhybridized p orbital available for pi bond formation.

Which hybridization scheme allows the formation of at least one pi (p) bond?Group of answer choicessp2sp3dsp3d2sp3

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