If the number of chromosomes in S-phase is 24 then what will be the number of chromosome present in anaphase of mitosis :-

To determine the number of chromosomes present in anaphase of mitosis, we need to understand the process of mitosis and how the number of chromosomes changes during each phase.

Mitosis is a type of cell division that results in the formation of two identical daughter cells. It consists of several phases, including prophase, metaphase, anaphase, and telophase.

During prophase, the chromosomes condense and become visible. In metaphase, the chromosomes align at the center of the cell. In anaphase, the sister chromatids separate and move towards opposite poles of the cell. Finally, in telophase, the chromosomes reach the poles and the cell starts to divide.

In S-phase, which occurs before mitosis, the DNA is replicated, resulting in two identical copies of each chromosome. Therefore, if the number of chromosomes in S-phase is 24, it means that there are 24 pairs of sister chromatids.

During anaphase, these sister chromatids separate and move towards opposite poles of the cell. Each chromatid is considered a separate chromosome. Therefore, the number of chromosomes in anaphase will be double the number of chromatids in S-phase.

Since there are 24 pairs of sister chromatids in S-phase, the number of chromosomes in anaphase will be 24 x 2 = 48.

Therefore, the number of chromosomes present in anaphase of mitosis, given that the number of chromosomes in S-phase is 24, will be 48.