#145909Report this questionThere was water leaking from a tank. After one day, the volume of water in the tank decreased by 3 ℓ. This was 7.5% of original volume of water in the tank.a) The volume of water in the tank after one day was % of the original volume.b) The volume of water in the tank was ℓ after one day.
Question
#145909Report this questionThere was water leaking from a tank. After one day, the volume of water in the tank decreased by 3 ℓ. This was 7.5% of original volume of water in the tank.a) The volume of water in the tank after one day was % of the original volume.b) The volume of water in the tank was ℓ after one day.
Solution
a) If 3 liters of water is 7.5% of the original volume, then the volume of water in the tank after one day would be 100% - 7.5% = 92.5% of the original volume.
b) To find the original volume of water in the tank, we can set up the equation 3 liters = 7.5% of the original volume. Solving for the original volume gives us 3 liters / 0.075 = 40 liters. Therefore, after one day, the volume of water in the tank would be 40 liters - 3 liters = 37 liters.
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