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A girl counted in the following way on the fingers of her left hand : She started by calling the thumb 1, the index finger 2, middle finger 3, ring finger 4, little finger 5 and then reversed direction calling the ring finger 6, middle finger 7 and so on. She counted upto 1995. She ended counting on which finger ?

Question

A girl counted in the following way on the fingers of her left hand : She started by calling the thumb 1, the index finger 2, middle finger 3, ring finger 4, little finger 5 and then reversed direction calling the ring finger 6, middle finger 7 and so on. She counted upto 1995. She ended counting on which finger ?

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Solution

The girl is counting in a sequence of 1 to 5 and then 5 to 1, which makes a total of 9 counts.

To find out on which finger she ended, we need to find the remainder when 1995 is divided by 9.

1995 divided by 9 equals 221 remainder 6.

So, she ended on the 6th count of the sequence.

The sequence is: thumb (1), index (2), middle (3), ring (4), little (5), ring (6), middle (7), index (8), thumb (9).

Therefore, she ended on the ring finger.

This problem has been solved

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