The first line contains the integer , the number of students' records. The next lines contain the names and marks obtained by a student, each value separated by a space. The final line contains query_name, the name of a student to query.ConstraintsOutput FormatPrint one line: The average of the marks obtained by the particular student correct to 2 decimal places.

It seems like you're asking for a Python solution to a problem where you have a list of student records and you want to find the average mark of a particular student. Here's a step-by-step solution:

1. First, we need to get the number of student records. We can do this using the input() function in Python, which reads a line of text from the user. Since this function returns a string, we need to convert this to an integer using the int() function.

n = int(input())

2. Next, we need to read the student records. We can do this in a loop that runs n times. In each iteration of the loop, we read a line of text, split it into a name and a mark, and store it in a dictionary.

records = {}
for _ in range(n):
    name, *marks = input().split()
    marks = list(map(float, marks))
    records[name] = marks

3. Then, we need to read the name of the student to query. We can do this using the input() function again.

query_name = input()

4. Finally, we need to compute and print the average mark of the queried student. We can do this by summing up the marks of the student (using the sum() function) and dividing by the number of marks (using the len() function). We use the format() function to print the result with 2 decimal places.

average = sum(records[query_name]) / len(records[query_name])
print("{:.2f}".format(average))

This is the complete Python program:

n = int(input())
records = {}
for _ in range(n):
    name, *marks = input().split()
    marks = list(map(float, marks))
    records[name] = marks
query_name = input()
average = sum(records[query_name]) / len(records[query_name])
print("{:.2f}".format(average))