Using whatever method you prefer, solve this equation: 𝑗2+22j​ +2 == 66

The equation you've provided seems to be a quadratic equation in the form of j^2 + 22j + 2 = 66. Let's solve it step by step:

Step 1: Rewrite the equation First, we need to rewrite the equation in the standard form of a quadratic equation, which is ax^2 + bx + c = 0. So, we subtract 66 from both sides of the equation to get:

j^2 + 22j + 2 - 66 = 0

This simplifies to:

j^2 + 22j - 64 = 0

Step 2: Factor