The error you're seeing is a NumberFormatException. This exception is thrown to indicate that the application has attempted to convert a string to one of the numeric types, but that the string does not have the appropriate format.

In your case, the error is occurring because you're trying to parse the string " 091" to an integer using the Integer.parseInt() method. However, this string starts with a space, which is not a valid character for a number.

Here's how you can fix the issue:

1. Initialize the `rev_num` variable as an empty string (`""`) instead of a string with a space (`" "`).

2. Remove the extra assignment in the line `num = num /= 10;`. It should be `num /= 10;`.

Here's the corrected code:

```java
public class Hello {
public static void main(String args[]) {
int num = 190;
String rev_num = "";

while (num != 0) {
int digit = num % 10;
rev_num = rev_num + digit;
num /= 10;
}

System.out.println(Integer.parseInt(rev_num));
}
}
```

With these corrections, the code should run without errors and print the reversed number as output.

Question

The error you're seeing is a NumberFormatException. This exception is thrown to indicate that the application has attempted to convert a string to one of the numeric types, but that the string does not have the appropriate format.

In your case, the error is occurring because you're trying to parse the string " 091" to an integer using the Integer.parseInt() method. However, this string starts with a space, which is not a valid character for a number.

Here's how you can fix the issue:

1. Initialize the `rev_num` variable as an empty string (`""`) instead of a string with a space (`" "`).

2. Remove the extra assignment in the line `num = num /= 10;`. It should be `num /= 10;`.

Here's the corrected code:

```java
public class Hello {
    public static void main(String args[]) {
        int num = 190;
        String rev_num = "";
        
        while (num != 0) {
            int digit = num % 10;
            rev_num = rev_num + digit;
            num /= 10;
        }
        
        System.out.println(Integer.parseInt(rev_num));
    }
}
```

With these corrections, the code should run without errors and print the reversed number as output.

Knowee AI · Accepted Answer

The error you're seeing is a NumberFormatException. This exception is thrown to indicate that the application has attempted to convert a string to one of the numeric types, but that the string does not have the appropriate format.

In your case, the error is occurring because you're trying to parse the string " 091" to an integer using the Integer.parseInt() method. However, this string starts with a space, which is not a valid character for a number.

Here's how you can fix the issue:

1. Initialize the `rev_num` variable as an empty string (`""`) instead of a string with a space (`" "`).

2. Remove the extra assignment in the line `num = num /= 10;`. It should be `num /= 10;`.

Here's the corrected code:

```java
public class Hello {
    public static void main(String args[]) {
        int num = 190;
        String rev_num = "";
        
        while (num != 0) {
            int digit = num % 10;
            rev_num = rev_num + digit;
            num /= 10;
        }
        
        System.out.println(Integer.parseInt(rev_num));
    }
}
```

With these corrections, the code should run without errors and print the reversed number as output.

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