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Density of the material of a paper is given as 0.5 gcm−3. The mass of the paper is 1 g and its length andbreadth are 10 cm and 5 cm, respectively. Arrangethe following steps in a sequence to find the thick-ness of the paper.(a) The thickness of the paper is= volume of the paperlength breadth( )V×(b) The density (d) of the material of the paper is= mass of the papervolume of the paper( )( )mV(c) Then the volume (V) of the paper= mass of the paperdensity of the paper( )( )md(d) The volume (V) of the paper is = length× breadth × thickness of the paper.(a) abcd (b) badc(c) abdc (d) bcda

Question

Density of the material of a paper is given as 0.5 gcm−3. The mass of the paper is 1 g and its length andbreadth are 10 cm and 5 cm, respectively. Arrangethe following steps in a sequence to find the thick-ness of the paper.(a) The thickness of the paper is= volume of the paperlength breadth( )V×(b) The density (d) of the material of the paper is= mass of the papervolume of the paper( )( )mV(c) Then the volume (V) of the paper= mass of the paperdensity of the paper( )( )md(d) The volume (V) of the paper is = length× breadth × thickness of the paper.(a) abcd (b) badc(c) abdc (d) bcda

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Solution

The correct sequence to find the thickness of the paper is:

(c) Then the volume (V) of the paper = mass of the paper / density of the paper (md) (b) The density (d) of the material of the paper is = mass of the paper / volume of the paper (mV) (d) The volume (V) of the paper is = length × breadth × thickness of the paper (a) The thickness of the paper is = volume of the paper / (length × breadth) (V × ())

Therefore, the correct sequence is (cbda).

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