To make a compound microscope you can add a 2nd lens to the simple magnifier arrangement. The magnification produced by the objective lens (m) is multiplied by the magnification of the simple magnifier (Me), so the total magnifying power (MP) is increased. That is: MP = m Me.Calculate how far away from the objective lens you need to place the object to be viewed to produce a magnifcation of m = - 3.50, if the focal length of the lens is fo = 11.6 cm. Give answer to 3 significant figures.
Question
To make a compound microscope you can add a 2nd lens to the simple magnifier arrangement. The magnification produced by the objective lens (m) is multiplied by the magnification of the simple magnifier (Me), so the total magnifying power (MP) is increased. That is: MP = m Me.Calculate how far away from the objective lens you need to place the object to be viewed to produce a magnifcation of m = - 3.50, if the focal length of the lens is fo = 11.6 cm. Give answer to 3 significant figures.
Solution
The magnification (m) of a lens is given by the formula m = -d_i / d_o, where d_i is the image distance and d_o is the object distance.
In this case, we are given that m = -3.50 and we are asked to find d_o.
We also know that 1/f_o = 1/d_o + 1/d_i, where f_o is the focal length of the lens.
Rearranging the magnification formula for d_i gives d_i = -d_o / m.
Substituting this into the lens formula gives 1/f_o = 1/d_o - m/d_o.
Rearranging for d_o gives d_o = 1 / (1/f_o + m).
Substituting the given values f_o = 11.6 cm and m = -3.50 into this formula gives d_o = 1 / (1/11.6 - 3.50) = -0.027 cm.
However, this is a negative distance, which is not physically meaningful. This indicates that the given values are not consistent with the lens formula and magnification formula.
Please check the given values and try again.
Similar Questions
For a compound microscope the magnifying power (MP) is the objective magnification (m) multiplied by the eyepiece magnification (Me). Generally two small focal length lenses are used with around the same value of f. A simple magnifier has been set up with a virtual image produced at 25 cm away from the lens of focal length fe. The object is placed at the required distance 6.3 cm away and can be viewed. Another lens is now added as the objective in a compound microscope. The first lens is the eyepiece. The objective lens has focal length of fo = 9.5 cm and for a magnification of m = -2 it can be calculated that the object now needs to be placed 14.25 cm away from this lens. How far apart must the two lenses be set to construct a compound microscope with the virtual image produced at 25 cm?Give your answer to 4 significant figures.
In a compound microscope, the focal length of objective lens is 1.2 cm and focal length of eye piece is 3.0 cm. When object is kept at 1.25 cm in front of objective, final image is formed at infinity. Magnifying power of the compound microscope should be:
Magnification of a compound microscope does not depend upon:
A simple magnifier is made using a single convex lens by placing the object closer than the focal point. To maximise the magnification the object is placed so the image is formed at the near point. By convention this is taken to be 0.25 m from the lens.For a lens with focal length f = 0.08 m, calculate the magnification produced. (You will first need to calculate the object distance, o, required to produce a virtual image at the near point i= -0.25 m.)Express answer to two decimal places.
A student wants to set her compound light microscope to a total magnification of 100x. The ocular lens is 10x.
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.