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Solve for a๐‘Ž in the following equation: 17a+23=a17๐‘Ž+23=๐‘ŽA.a=โˆ’7๐‘Ž=โˆ’7B.a=79๐‘Ž=79C.a=718๐‘Ž=718D.a=312

Question

Solve for a๐‘Ž in the following equation: 17a+23=a17๐‘Ž+23=๐‘ŽA.a=โˆ’7๐‘Ž=โˆ’7B.a=79๐‘Ž=79C.a=718๐‘Ž=718D.a=312

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Solution

The equation you provided seems to be a bit jumbled, but I'll assume you're asking for the solution to the equation 17a + 23 = a. Here's how you can solve it:

Step 1: Subtract 'a' from both sides of the equation to get: 17a - a + 23 = 0

Step 2: Simplify the left side of the equation to get: 16a + 23 = 0

Step 3: Subtract 23 from both sides of the equation to isolate the term with 'a': 16a = -23

Step 4: Divide both sides of the equation by 16 to solve for 'a': a = -23/16

So, the solution to the equation 17a + 23 = a is a = -23/16. This doesn't match any of the options you provided (A. a = -7, B. a = 79, C. a = 718, D. a = 312), so there might have been a mistake in the problem or the answer choices.

This problem has been solved

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