How many moles of oxygen atoms are there in 0.500 mol of hydrated iron(II) ammonium sulfate, (NH4)2Fe(SO4)2•6H2O(s)?A. 4.00B. 7.00C. 8.00D. 14.00
Question
How many moles of oxygen atoms are there in 0.500 mol of hydrated iron(II) ammonium sulfate, (NH4)2Fe(SO4)2•6H2O(s)?A. 4.00B. 7.00C. 8.00D. 14.00
Solution
To answer this question, we first need to understand the molecular formula of hydrated iron(II) ammonium sulfate, which is (NH4)2Fe(SO4)2•6H2O.
In this compound:
- There are 2 sulfate ions (SO4)2-. Each sulfate ion contains 4 oxygen atoms, so in total, there are 2*4 = 8 oxygen atoms from the sulfate ions.
- There are 6 water molecules (H2O). Each water molecule contains 1 oxygen atom, so in total, there are 6*1 = 6 oxygen atoms from the water molecules.
So, in one molecule of hydrated iron(II) ammonium sulfate, there are 8 + 6 = 14 oxygen atoms.
Since the question asks for the number of moles of oxygen atoms in 0.500 mol of the compound, and we know that there are 14 oxygen atoms in one molecule of the compound, we can simply multiply the number of moles of the compound by the number of oxygen atoms in one molecule of the compound.
So, 0.500 mol * 14 = 7.00 mol
Therefore, there are 7.00 moles of oxygen atoms in 0.500 mol of hydrated iron(II) ammonium sulfate. The correct answer is B. 7.00.
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