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Ball A is 1kg and ball B is 2kg. A student rolls ball A so that it hits ball B with 3N of force.Using Newton's 2nd law (𝐹=𝑚𝑎)(F=ma)left parenthesis, F, equals, m, a, right parenthesis and Newton's 3rd law, find the magnitude of the acceleration of each ball.Atomi Question

Question

Ball A is 1kg and ball B is 2kg. A student rolls ball A so that it hits ball B with 3N of force.Using Newton's 2nd law (𝐹=𝑚𝑎)(F=ma)left parenthesis, F, equals, m, a, right parenthesis and Newton's 3rd law, find the magnitude of the acceleration of each ball.Atomi Question

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Solution

First, let's use Newton's 2nd law (F=ma) to find the acceleration of each ball.

For ball A: The force exerted on ball A is 3N (this is the same force it exerted on ball B due to Newton's 3rd law - every action has an equal and opposite reaction). The mass of ball A is 1kg. So we can calculate the acceleration (a) as follows:

a = F/m a = 3N / 1kg a = 3 m/s²

So, the acceleration of ball A is 3 m/s².

For ball B: The force exerted on ball B is also 3N (the force exerted by ball A). The mass of ball B is 2kg. So we can calculate the acceleration (a) as follows:

a = F/m a = 3N / 2kg a = 1.5 m/s²

So, the acceleration of ball B is 1.5 m/s².

This problem has been solved

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