On a particular day, a salesman sold three types of toys. Each toy of the 3 varieties costs Rs.100, Rs.50, and Rs.25 respectively. If the total sale on that day was Rs.300 and the salesman sold at least one toy of each variety, find the maximum number of toys he could have sold.Choices:- 8 10 9 7
Question
On a particular day, a salesman sold three types of toys. Each toy of the 3 varieties costs Rs.100, Rs.50, and Rs.25 respectively. If the total sale on that day was Rs.300 and the salesman sold at least one toy of each variety, find the maximum number of toys he could have sold.Choices:- 8 10 9 7
Solution
To maximize the number of toys sold, the salesman should sell as many of the cheapest toy as possible.
Step 1: Since the salesman sold at least one toy of each variety, let's subtract the cost of one toy of each variety from the total sales.
Total sales = Rs.300 Cost of one toy of each variety = Rs.100 + Rs.50 + Rs.25 = Rs.175
So, the remaining amount = Rs.300 - Rs.175 = Rs.125
Step 2: Now, let's see how many of the cheapest toys (Rs.25) the salesman can sell with the remaining amount.
Number of Rs.25 toys = Rs.125 / Rs.25 = 5 toys
Step 3: Adding the one toy of each variety that the salesman sold, the total number of toys sold is:
Total number of toys = 5 (Rs.25 toys) + 1 (Rs.100 toy) + 1 (Rs.50 toy) + 1 (Rs.25 toy) = 8 toys
So, the maximum number of toys the salesman could have sold is 8. Therefore, the correct choice is 8.
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