A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if B and C assist him on every third day?
Question
A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if B and C assist him on every third day?
Solution
Sure, let's solve this step by step:
Step 1: First, we need to find out the one day's work of A, B, and C.
A's one day's work = 1/20 B's one day's work = 1/30 C's one day's work = 1/60
Step 2: Now, let's find out the combined work of A, B, and C for one day.
A, B, and C's one day's work = 1/20 + 1/30 + 1/60 = 1/10
Step 3: Now, let's find out the work done by A alone in two days and by A, B, and C on the third day.
Work done in 3 days = 2*(1/20) + 1/10 = 1/10 + 1/10 = 1/5
Step 4: Now, let's find out the number of days A can complete the work with B and C assisting him every third day.
Let's assume the work is completed in 'n' days. Since the work done in 3 days is 1/5, the work done in 'n' days will be n/5.
So, n/5 = 1 (since the whole work is considered as 1)
Solving for 'n', we get n = 5 days.
So, A can complete the work in 5 days with B and C assisting him every third day.
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