Two sinusoidal waves ๐ฆ1 (๐ฅ, ๐ก) and ๐ฆ1(๐ฅ, ๐ก) have the same wavelength and travel together in the samedirection along a string (say in x-direction). Their amplitudes are ๐ฆ10 = 4 ๐๐ and ๐ฆ20 = 3 ๐๐, and theirphase constants are 0 and ๐3 respectively. Find the amplitude and phase constant of the resultant wave andexpress the resultant in the standard wave format
Question
Two sinusoidal waves ๐ฆ1 (๐ฅ, ๐ก) and ๐ฆ1(๐ฅ, ๐ก) have the same wavelength and travel together in the samedirection along a string (say in x-direction). Their amplitudes are ๐ฆ10 = 4 ๐๐ and ๐ฆ20 = 3 ๐๐, and theirphase constants are 0 and ๐3 respectively. Find the amplitude and phase constant of the resultant wave andexpress the resultant in the standard wave format
Solution
To find the amplitude and phase constant of the resultant wave, we can use the principle of superposition.
The equation for the first wave is given by ๐ฆ1(๐ฅ, ๐ก) = ๐ฆ10 sin(๐๐ฅ - ฯ๐ก), where ๐ฆ10 is the amplitude and 0 is the phase constant.
The equation for the second wave is given by ๐ฆ2(๐ฅ, ๐ก) = ๐ฆ20 sin(๐๐ฅ - ฯ๐ก + ๐/3), where ๐ฆ20 is the amplitude and ๐/3 is the phase constant.
Since the waves have the same wavelength and travel in the same direction, their wave numbers (๐) and angular frequencies (ฯ) are equal.
Let's denote the resultant wave as ๐ฆ(๐ฅ, ๐ก). According to the principle of superposition, the resultant wave is the sum of the individual waves:
๐ฆ(๐ฅ, ๐ก) = ๐ฆ1(๐ฅ, ๐ก) + ๐ฆ2(๐ฅ, ๐ก) = ๐ฆ10 sin(๐๐ฅ - ฯ๐ก) + ๐ฆ20 sin(๐๐ฅ - ฯ๐ก + ๐/3)
To simplify this expression, we can use the trigonometric identity: sin(๐ + ๐) = sin ๐ cos ๐ + cos ๐ sin ๐.
๐ฆ(๐ฅ, ๐ก) = ๐ฆ10 sin(๐๐ฅ - ฯ๐ก) + ๐ฆ20 sin(๐๐ฅ - ฯ๐ก) cos(๐/3) + ๐ฆ20 cos(๐๐ฅ - ฯ๐ก) sin(๐/3)
Simplifying further, we have:
๐ฆ(๐ฅ, ๐ก) = (๐ฆ10 + ๐ฆ20 cos(๐/3)) sin(๐๐ฅ - ฯ๐ก) + ๐ฆ20 sin(๐๐ฅ - ฯ๐ก) sin(๐/3)
The amplitude of the resultant wave is given by the coefficient of sin(๐๐ฅ - ฯ๐ก), which is ๐ฆ10 + ๐ฆ20 cos(๐/3).
Substituting the given values, we have:
๐ฆ10 = 4 ๐๐ ๐ฆ20 = 3 ๐๐
๐ฆ(๐ฅ, ๐ก) = (4 + 3 cos(๐/3)) sin(๐๐ฅ - ฯ๐ก) + 3 sin(๐๐ฅ - ฯ๐ก) sin(๐/3)
To express the resultant wave in the standard wave format, we can simplify the expression further.
Using the trigonometric identity: sin(๐ + ๐) = sin ๐ cos ๐ + cos ๐ sin ๐, we can rewrite the expression as:
๐ฆ(๐ฅ, ๐ก) = (4 + 3 cos(๐/3)) sin(๐๐ฅ - ฯ๐ก) + 3/2 sin(2๐๐ฅ - 2ฯ๐ก + ๐/3)
Therefore, the amplitude of the resultant wave is (4 + 3 cos(๐/3)) ๐๐ and the phase constant is ๐/3. The resultant wave can be expressed in the standard wave format as:
๐ฆ(๐ฅ, ๐ก) = (4 + 3 cos(๐/3)) sin(๐๐ฅ - ฯ๐ก) + 3/2 sin(2๐๐ฅ - 2ฯ๐ก + ๐/3)
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