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Two sinusoidal waves ๐‘ฆ1 (๐‘ฅ, ๐‘ก) and ๐‘ฆ1(๐‘ฅ, ๐‘ก) have the same wavelength and travel together in the samedirection along a string (say in x-direction). Their amplitudes are ๐‘ฆ10 = 4 ๐‘š๐‘š and ๐‘ฆ20 = 3 ๐‘š๐‘š, and theirphase constants are 0 and ๐œ‹3 respectively. Find the amplitude and phase constant of the resultant wave andexpress the resultant in the standard wave format

Question

Two sinusoidal waves ๐‘ฆ1 (๐‘ฅ, ๐‘ก) and ๐‘ฆ1(๐‘ฅ, ๐‘ก) have the same wavelength and travel together in the samedirection along a string (say in x-direction). Their amplitudes are ๐‘ฆ10 = 4 ๐‘š๐‘š and ๐‘ฆ20 = 3 ๐‘š๐‘š, and theirphase constants are 0 and ๐œ‹3 respectively. Find the amplitude and phase constant of the resultant wave andexpress the resultant in the standard wave format

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Solution

To find the amplitude and phase constant of the resultant wave, we can use the principle of superposition.

The equation for the first wave is given by ๐‘ฆ1(๐‘ฅ, ๐‘ก) = ๐‘ฆ10 sin(๐‘˜๐‘ฅ - ฯ‰๐‘ก), where ๐‘ฆ10 is the amplitude and 0 is the phase constant.

The equation for the second wave is given by ๐‘ฆ2(๐‘ฅ, ๐‘ก) = ๐‘ฆ20 sin(๐‘˜๐‘ฅ - ฯ‰๐‘ก + ๐œ‹/3), where ๐‘ฆ20 is the amplitude and ๐œ‹/3 is the phase constant.

Since the waves have the same wavelength and travel in the same direction, their wave numbers (๐‘˜) and angular frequencies (ฯ‰) are equal.

Let's denote the resultant wave as ๐‘ฆ(๐‘ฅ, ๐‘ก). According to the principle of superposition, the resultant wave is the sum of the individual waves:

๐‘ฆ(๐‘ฅ, ๐‘ก) = ๐‘ฆ1(๐‘ฅ, ๐‘ก) + ๐‘ฆ2(๐‘ฅ, ๐‘ก) = ๐‘ฆ10 sin(๐‘˜๐‘ฅ - ฯ‰๐‘ก) + ๐‘ฆ20 sin(๐‘˜๐‘ฅ - ฯ‰๐‘ก + ๐œ‹/3)

To simplify this expression, we can use the trigonometric identity: sin(๐‘Ž + ๐‘) = sin ๐‘Ž cos ๐‘ + cos ๐‘Ž sin ๐‘.

๐‘ฆ(๐‘ฅ, ๐‘ก) = ๐‘ฆ10 sin(๐‘˜๐‘ฅ - ฯ‰๐‘ก) + ๐‘ฆ20 sin(๐‘˜๐‘ฅ - ฯ‰๐‘ก) cos(๐œ‹/3) + ๐‘ฆ20 cos(๐‘˜๐‘ฅ - ฯ‰๐‘ก) sin(๐œ‹/3)

Simplifying further, we have:

๐‘ฆ(๐‘ฅ, ๐‘ก) = (๐‘ฆ10 + ๐‘ฆ20 cos(๐œ‹/3)) sin(๐‘˜๐‘ฅ - ฯ‰๐‘ก) + ๐‘ฆ20 sin(๐‘˜๐‘ฅ - ฯ‰๐‘ก) sin(๐œ‹/3)

The amplitude of the resultant wave is given by the coefficient of sin(๐‘˜๐‘ฅ - ฯ‰๐‘ก), which is ๐‘ฆ10 + ๐‘ฆ20 cos(๐œ‹/3).

Substituting the given values, we have:

๐‘ฆ10 = 4 ๐‘š๐‘š ๐‘ฆ20 = 3 ๐‘š๐‘š

๐‘ฆ(๐‘ฅ, ๐‘ก) = (4 + 3 cos(๐œ‹/3)) sin(๐‘˜๐‘ฅ - ฯ‰๐‘ก) + 3 sin(๐‘˜๐‘ฅ - ฯ‰๐‘ก) sin(๐œ‹/3)

To express the resultant wave in the standard wave format, we can simplify the expression further.

Using the trigonometric identity: sin(๐‘Ž + ๐‘) = sin ๐‘Ž cos ๐‘ + cos ๐‘Ž sin ๐‘, we can rewrite the expression as:

๐‘ฆ(๐‘ฅ, ๐‘ก) = (4 + 3 cos(๐œ‹/3)) sin(๐‘˜๐‘ฅ - ฯ‰๐‘ก) + 3/2 sin(2๐‘˜๐‘ฅ - 2ฯ‰๐‘ก + ๐œ‹/3)

Therefore, the amplitude of the resultant wave is (4 + 3 cos(๐œ‹/3)) ๐‘š๐‘š and the phase constant is ๐œ‹/3. The resultant wave can be expressed in the standard wave format as:

๐‘ฆ(๐‘ฅ, ๐‘ก) = (4 + 3 cos(๐œ‹/3)) sin(๐‘˜๐‘ฅ - ฯ‰๐‘ก) + 3/2 sin(2๐‘˜๐‘ฅ - 2ฯ‰๐‘ก + ๐œ‹/3)

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