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What is the output of the following function calldef fun1(name, age=20):    print(name, age) fun1('Emma', 25)Emma 25Emma 20Emma 22

Question

What is the output of the following function calldef fun1(name, age=20):    print(name, age) fun1('Emma', 25)Emma 25Emma 20Emma 22

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Solution

The output of the function call fun1('Emma', 25) will be Emma 25.

Here's the step by step explanation:

  1. The function fun1 is defined with two parameters: name and age. The age parameter has a default value of 20.

  2. When you call the function with the arguments 'Emma' and 25, these values are passed to the name and age parameters respectively.

  3. Inside the function, the print statement prints the values of name and age, which are 'Emma' and 25.

  4. Therefore, the output is Emma 25.

The other outputs Emma 20 and Emma 22 are not produced by this function call. If you called fun1('Emma'), the output would be Emma 20 because of the default value for age. There's no function call here that would produce Emma 22.

This problem has been solved

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