The network mask for an IP address of 192.168.1.1/27 is 255.255.255.224.

Here's how you can calculate it:

1. The /27 at the end of the IP address means that the first 27 bits are used for the network address, leaving the remaining 5 bits for host addresses.

2. In binary, 27 bits gives you 255.255.255.224 in decimal.

This is because the first 8 bits are all 1s, which is 255 in decimal. This is repeated for the next two octets. For the last octet, you have 3 bits set to 1 and 5 bits set to 0. In binary, 11100000 equals 224 in decimal.

So, the network mask is 255.255.255.224.

Question

The network mask for an IP address of 192.168.1.1/27 is 255.255.255.224.

Here's how you can calculate it:

1. The /27 at the end of the IP address means that the first 27 bits are used for the network address, leaving the remaining 5 bits for host addresses.

2. In binary, 27 bits gives you 255.255.255.224 in decimal.

This is because the first 8 bits are all 1s, which is 255 in decimal. This is repeated for the next two octets. For the last octet, you have 3 bits set to 1 and 5 bits set to 0. In binary, 11100000 equals 224 in decimal.

So, the network mask is 255.255.255.224.

Knowee AI · Accepted Answer

The network mask for an IP address of 192.168.1.1/27 is 255.255.255.224.

Here's how you can calculate it:

1. The /27 at the end of the IP address means that the first 27 bits are used for the network address, leaving the remaining 5 bits for host addresses.

2. In binary, 27 bits gives you 255.255.255.224 in decimal.

This is because the first 8 bits are all 1s, which is 255 in decimal. This is repeated for the next two octets. For the last octet, you have 3 bits set to 1 and 5 bits set to 0. In binary, 11100000 equals 224 in decimal.

So, the network mask is 255.255.255.224.

What is the network mask if the address is 192.168.1.1/27

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