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Mack's Knick-Knacks is having a clearance sale on costume jewelry sets next week. The manager wants to find how much to charge per set in order to sell $100 worth. Based on previous clearance events, the manager knows he can use the expression –7p+75 to find the number of sets he will sell based on a set's price, p.Which equation can the manager use to find the price per set needed to sell $100 worth?100=p(–7p+75)100p=p(–7p+75)To the nearest dollar, what is the highest price the manager can use to sell $100 worth of costume jewelry sets?$Submit

Question

Mack's Knick-Knacks is having a clearance sale on costume jewelry sets next week. The manager wants to find how much to charge per set in order to sell 100worth.Basedonpreviousclearanceevents,themanagerknowshecanusetheexpression7p+75tofindthenumberofsetshewillsellbasedonasetsprice,p.Whichequationcanthemanagerusetofindthepricepersetneededtosell100 worth. Based on previous clearance events, the manager knows he can use the expression –7p+75 to find the number of sets he will sell based on a set's price, p.Which equation can the manager use to find the price per set needed to sell 100 worth?100=p(–7p+75)100p=p(–7p+75)To the nearest dollar, what is the highest price the manager can use to sell 100worthofcostumejewelrysets?100 worth of costume jewelry sets?Submit

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Solution

The manager can use the equation 100 = p(-7p + 75) to find the price per set needed to sell 100worthofcostumejewelrysets.Thisequationisderivedfromtheexpression7p+75,whichrepresentsthenumberofsetshewillsellbasedonasetsprice,p.Bysettingthisexpressionequalto100 worth of costume jewelry sets. This equation is derived from the expression -7p + 75, which represents the number of sets he will sell based on a set's price, p. By setting this expression equal to 100, the manager can solve for p to find the price per set.

To solve for p, we can follow these steps:

  1. Distribute p to both terms inside the parentheses: 100 = -7p^2 + 75p
  2. Rearrange the equation to set it equal to zero: 7p^2 - 75p + 100 = 0
  3. This is a quadratic equation in the form of ax^2 + bx + c = 0. We can solve for p using the quadratic formula, p = [-b ± sqrt(b^2 - 4ac)] / (2a). Here, a = 7, b = -75, and c = 100.
  4. Substituting these values into the quadratic formula gives us two possible solutions for p.

After calculating, we find that the two possible prices are approximately 8.93and8.93 and 1.59. Since the question asks for the highest price, the manager can charge approximately 9persettosell9 per set to sell 100 worth of costume jewelry sets.

This problem has been solved

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