On placing a copper coin in a test tube containing green ferrous sulphate solution, it willbe observed that the ferrous sulphate solution(a) turns blue, and a grey substance is deposited on the copper coin.(b) turns colourless and a grey substance is deposited on the copper coin.(c) turns colourless and a reddish–brown substance is deposited on the copper coin.(d) remains green with no change in the copper coin.
Question
On placing a copper coin in a test tube containing green ferrous sulphate solution, it willbe observed that the ferrous sulphate solution(a) turns blue, and a grey substance is deposited on the copper coin.(b) turns colourless and a grey substance is deposited on the copper coin.(c) turns colourless and a reddish–brown substance is deposited on the copper coin.(d) remains green with no change in the copper coin.
Solution
The correct answer is (a) turns blue, and a grey substance is deposited on the copper coin.
Here's the step by step explanation:
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When a copper coin is placed in a test tube containing green ferrous sulphate solution, a displacement reaction takes place. This is because copper is more reactive than iron.
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In this displacement reaction, copper displaces iron from the ferrous sulphate solution. The equation for this reaction is: Cu(s) + FeSO4(aq) -> CuSO4(aq) + Fe(s)
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As a result of this reaction, the green color of the ferrous sulphate solution changes to blue because of the formation of copper sulphate.
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The grey substance that is deposited on the copper coin is iron, which has been displaced from the ferrous sulphate solution by copper.
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