A flight attendant looked over a list of recent passengers. The list contained passengers' Frequent Flyer status as well as the number of bags checked.0 checked bags 1 checked bagBronze status 1 7Silver status 7 5Gold status 2 10What is the probability that a randomly selected passenger does not have silver status and does not have 1 checked bag?Simplify any fractions.Submit
Question
A flight attendant looked over a list of recent passengers. The list contained passengers' Frequent Flyer status as well as the number of bags checked.0 checked bags 1 checked bagBronze status 1 7Silver status 7 5Gold status 2 10What is the probability that a randomly selected passenger does not have silver status and does not have 1 checked bag?Simplify any fractions.Submit
Solution
To solve this problem, we first need to understand the total number of passengers. We can find this by adding up all the numbers in the table:
Bronze with 0 bags: 1 Bronze with 1 bag: 7 Silver with 0 bags: 7 Silver with 1 bag: 5 Gold with 0 bags: 2 Gold with 1 bag: 10
Total passengers = 1 + 7 + 7 + 5 + 2 + 10 = 32 passengers
Next, we need to find the number of passengers who do not have silver status and do not have 1 checked bag. This would be the sum of Bronze with 0 bags and Gold with 0 bags:
Bronze with 0 bags: 1 Gold with 0 bags: 2
Total passengers without silver status and without 1 checked bag = 1 + 2 = 3 passengers
The probability of a randomly selected passenger not having silver status and not having 1 checked bag is therefore 3 out of 32, or 3/32.
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