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What are the zeroes of f(x) = x2 − 2x − 3? x = −3, 1 x = −3, −1 x = 3, 1 x = 3, −1

Question

What are the zeroes of f(x) = x2 − 2x − 3? x = −3, 1 x = −3, −1 x = 3, 1 x = 3, −1

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Solution

Para encontrar las raíces de la función f(x)=x22x3 f(x) = x^2 - 2x - 3 , seguimos estos pasos:

  1. Identificar la ecuación cuadrática: La ecuación dada es x22x3=0 x^2 - 2x - 3 = 0 .

  2. Factorizar la ecuación cuadrática: Buscamos dos números que multiplicados den 3-3 (el término constante) y sumados den 2-2 (el coeficiente del término lineal). Esos números son 3-3 y 11.

  3. Escribir la ecuación factorizada: La ecuación se puede escribir como: (x3)(x+1)=0 (x - 3)(x + 1) = 0

  4. Encontrar las raíces: Para que el producto sea cero, uno de los factores debe ser cero. Entonces, resolvemos: x3=0ox+1=0 x - 3 = 0 \quad \text{o} \quad x + 1 = 0 x=3ox=1 x = 3 \quad \text{o} \quad x = -1

Por lo tanto, las raíces de la función f(x)=x22x3 f(x) = x^2 - 2x - 3 son x=3 x = 3 y x=1 x = -1 .

La respuesta correcta es: x=3,1 x = 3, -1 .

This problem has been solved

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