To solve this problem, we can use the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.

Here, the two sides of the right triangle are the widths of Springdale Street and Westford Avenue, and the hypotenuse is the distance between the two opposite corners of the intersection.

Step 1: Square the width of Springdale Street (8 metres).
8^2 = 64 square metres.

Step 2: Square the width of Westford Avenue (5 metres).
5^2 = 25 square metres.

Step 3: Add the results of step 1 and step 2.
64 + 25 = 89 square metres.

Step 4: Take the square root of the result from step 3 to find the length of the hypotenuse.
The square root of 89 is approximately 9.4 metres.

So, the distance between the two opposite corners of the intersection is approximately 9.4 metres.

Question

To solve this problem, we can use the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.

Here, the two sides of the right triangle are the widths of Springdale Street and Westford Avenue, and the hypotenuse is the distance between the two opposite corners of the intersection.

Step 1: Square the width of Springdale Street (8 metres).
8^2 = 64 square metres.

Step 2: Square the width of Westford Avenue (5 metres).
5^2 = 25 square metres.

Step 3: Add the results of step 1 and step 2.
64 + 25 = 89 square metres.

Step 4: Take the square root of the result from step 3 to find the length of the hypotenuse.
The square root of 89 is approximately 9.4 metres.

So, the distance between the two opposite corners of the intersection is approximately 9.4 metres.

Knowee AI · Accepted Answer

To solve this problem, we can use the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.

Here, the two sides of the right triangle are the widths of Springdale Street and Westford Avenue, and the hypotenuse is the distance between the two opposite corners of the intersection.

Step 1: Square the width of Springdale Street (8 metres).
8^2 = 64 square metres.

Step 2: Square the width of Westford Avenue (5 metres).
5^2 = 25 square metres.

Step 3: Add the results of step 1 and step 2.
64 + 25 = 89 square metres.

Step 4: Take the square root of the result from step 3 to find the length of the hypotenuse.
The square root of 89 is approximately 9.4 metres.

So, the distance between the two opposite corners of the intersection is approximately 9.4 metres.

Springdale Street and Westford Avenue intersect. If Springdale Street is 8 metres wide and Westford Avenue is 5 metres wide, what is the distance between two opposite corners of the intersection? If necessary, round to the nearest tenth.

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