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Three years ago, the average age of X, Y and Z was 27 years and that of Y and Z, 5 years ago was 20 years. X’s present age is:Options :30 years35 years40 years48 years

Question

Three years ago, the average age of X, Y and Z was 27 years and that of Y and Z, 5 years ago was 20 years. X’s present age is:Options :30 years35 years40 years48 years

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Solution

Let's solve this step by step:

  1. According to the problem, three years ago, the average age of X, Y, and Z was 27 years. This means that the total age of X, Y, and Z three years ago was 27 * 3 = 81 years.

  2. The problem also states that five years ago, the average age of Y and Z was 20 years. This means that the total age of Y and Z five years ago was 20 * 2 = 40 years.

  3. Now, we know that the total age of Y and Z has increased by 5 years for each of them from five years ago to three years ago. So, the total age of Y and Z three years ago was 40 + 5*2 = 50 years.

  4. Now, if we subtract the total age of Y and Z three years ago from the total age of X, Y, and Z three years ago, we get the age of X three years ago. So, X was 81 - 50 = 31 years old three years ago.

  5. Therefore, X's present age is 31 + 3 = 34 years.

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