Four bells began to toll at 5, 8, 9, and 10 seconds respectively. In 2 hours, how many times will they toll together?
Question
Four bells began to toll at 5, 8, 9, and 10 seconds respectively. In 2 hours, how many times will they toll together?
Solution
To solve this problem, we first need to find the least common multiple (LCM) of the four numbers, which represent the intervals at which each bell tolls. The LCM of 5, 8, 9, and 10 seconds is 360 seconds, or 6 minutes. This means that all four bells will toll together every 6 minutes.
Next, we need to determine how many 6-minute intervals are in 2 hours. There are 60 minutes in an hour, so 2 hours is 120 minutes. Dividing 120 by 6, we get 20.
Therefore, the four bells will toll together 20 times in 2 hours.
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