ncreasing order of bond angle in the following species is                                    OCl2,               SCl2,      BCl3                                      I                      II           III II < I < III I < II < III III < II < I I < III < II

The bond angle in a molecule is determined by the repulsion between the electron pairs in the valence shell of the central atom. The greater the repulsion, the larger the bond angle.

1. OCl2: Oxygen is more electronegative than chlorine, so the electron pairs are pulled closer to the oxygen atom, reducing the repulsion and thus the bond angle.

2. SCl2: Sulfur is less electronegative than chlorine, so the electron pairs are not pulled as close to the sulfur atom. This increases the repulsion and thus the bond angle.

3. BCl3: Boron is less electronegative than chlorine, and it also has an empty p-orbital which can accommodate the electron pairs from the chlorine atoms. This further increases the repulsion and thus the bond angle.

So, the increasing order of bond angle is OCl2 < SCl2 < BCl3, or in your notation, II < I < III.