def sum_multiply(a,b,*more): sum_value = a+b m_value = a*b for i in more: sum_value += i m_value*=i return sum_value,m_values_m = sum_multiply(2,3,4)print(s_m)
Question
def sum_multiply(a,b,more): sum_value = a+b m_value = ab for i in more: sum_value += i m_value*=i return sum_value,m_values_m = sum_multiply(2,3,4)print(s_m)
Solution
It seems like you have a Python function here named sum_multiply which takes at least two arguments, a and b, and then any number of additional arguments (*more). The function calculates the sum and the product of all the arguments provided.
However, there is a typo in your return statement. You're returning m_values which is not defined in your function. You should return m_value instead. Also, in your print statement, you're trying to print s_m which is not defined. You should print m instead if you want to print the result of the function.
Here is the corrected code:
def sum_multiply(a, b, *more):
sum_value = a + b
m_value = a * b
for i in more:
sum_value += i
m_value *= i
return sum_value, m_value
s, m = sum_multiply(2, 3, 4)
print(s, m)
In this corrected code, the function sum_multiply is called with arguments 2, 3, and 4. The sum and product of these numbers are calculated and returned. The returned values are then stored in the variables s and m, and then printed.
Similar Questions
What will be the output of following code?def sum_multiply(a,b,*more): sum_value = a+b m_value = a*b for i in more: sum_value += i m_value*=i return sum_value,m_values_m = sum_multiply(2,3,4)print(s_m)infoYou have max 2 attempts to score in this question.Attempts left:1/2OptionsThis problem has only one correct answer9,24(9,24)Error(5,6)warningWrong Answer, Attempt Again
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