The z-score above which 10% of a normally distributed population exists, z0.10 , is closest to
Question
The z-score above which 10% of a normally distributed population exists, z0.10 , is closest to
Solution
To find the z-score above which 10% of a normally distributed population exists, we need to determine the z-score corresponding to the 90th percentile (since 100% - 10% = 90%).
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Identify the cumulative probability: We need the z-score for which the cumulative probability is 0.90.
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Use the standard normal distribution table or a calculator: Look up the cumulative probability of 0.90 in the z-table or use a statistical calculator to find the corresponding z-score.
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Find the z-score: The z-score corresponding to the 90th percentile is approximately 1.28.
Therefore, the z-score above which 10% of a normally distributed population exists, , is closest to 1.28.
Similar Questions
If a z score of 2.33 is obtained, we know that the person’s raw scorea.is lower than the scores of most others on the testb.is about averagec.is above averaged.falls at the 84th percentile
A random variable X has a normal distribution, with a mean of 10 and a standard deviation of 2. What will be the z-score for a value of 5?a.-2.5b.-5.0c.5.0d.2.5
What is the mean of the z-scores?Question 2Answera.0.5b.0c.1
Which of these z-scores might represent a very difficult item in the normal distribution?a.+2.33b.−.52c.−2.06d.+.20
how to fine this. The confidence level is 99%, so the Z-score is approximately 2.576 (you can find this value in a standard Z-table or using a calculator)
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