To solve this problem, we first consider the vowels EA and I as a single letter. So, we have the letters L, N, D, G, and 'vowel group' to arrange, which gives us 5! (5 factorial) ways to arrange these letters.

5! = 5*4*3*2*1 = 120

Next, within the 'vowel group' of EA and I, we have 3! (3 factorial) ways to arrange these letters.

3! = 3*2*1 = 6

So, the total number of ways to arrange the letters in 'LEADING' such that the vowels always come together is 120*6 = 720.

Therefore, the answer is C720.

Question

To solve this problem, we first consider the vowels EA and I as a single letter. So, we have the letters L, N, D, G, and 'vowel group' to arrange, which gives us 5! (5 factorial) ways to arrange these letters.

5! = 5*4*3*2*1 = 120

Next, within the 'vowel group' of EA and I, we have 3! (3 factorial) ways to arrange these letters.

3! = 3*2*1 = 6

So, the total number of ways to arrange the letters in 'LEADING' such that the vowels always come together is 120*6 = 720.

Therefore, the answer is C720.

Knowee AI · Accepted Answer

To solve this problem, we first consider the vowels EA and I as a single letter. So, we have the letters L, N, D, G, and 'vowel group' to arrange, which gives us 5! (5 factorial) ways to arrange these letters.

5! = 5*4*3*2*1 = 120

Next, within the 'vowel group' of EA and I, we have 3! (3 factorial) ways to arrange these letters.

3! = 3*2*1 = 6

So, the total number of ways to arrange the letters in 'LEADING' such that the vowels always come together is 120*6 = 720.

Therefore, the answer is C720.

In how many different ways can the letters of the word 'LEADING' be arranged in such a way that the vowels always come together?A360B480C720D5040ENone of these

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