Calculate the heat of the following reaction:3Fe2O3 + CO –> 2Fe3O4 + CO2Given the following heats of formation:Fe2O3 ΔH°f= -824.2 kJ/molCO ΔH°f= -110.5 kJ/molFe3O4 ΔH°f= -1118.4 kJ/molCO2 ΔH°f= -393.5 kJ/molGroup of answer choices-47.2 kJ-27.2 kJ-87.2 kJ-67.2 kJ
Question
Calculate the heat of the following reaction:3Fe2O3 + CO –> 2Fe3O4 + CO2Given the following heats of formation:Fe2O3 ΔH°f= -824.2 kJ/molCO ΔH°f= -110.5 kJ/molFe3O4 ΔH°f= -1118.4 kJ/molCO2 ΔH°f= -393.5 kJ/molGroup of answer choices-47.2 kJ-27.2 kJ-87.2 kJ-67.2 kJ
Solution
To calculate the heat of the reaction, we need to use the formula:
ΔH°rxn = Σ ΔH°f (products) - Σ ΔH°f (reactants)
For the products, we have:
2Fe3O4 + CO2 = 2(-1118.4 kJ/mol) + 1(-393.5 kJ/mol) = -2630.3 kJ
For the reactants, we have:
3Fe2O3 + CO = 3(-824.2 kJ/mol) + 1(-110.5 kJ/mol) = -2583.1 kJ
Substituting these values into the formula, we get:
ΔH°rxn = -2630.3 kJ - (-2583.1 kJ) = -47.2 kJ
So, the heat of the reaction is -47.2 kJ.
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