Suppose you separate a 3.02 g mixture of sand and salt. You recover 1.38 g of salt and 1.32 g of sand. What is the percent recovery of the mixture?Type answer:
Question
Suppose you separate a 3.02 g mixture of sand and salt. You recover 1.38 g of salt and 1.32 g of sand. What is the percent recovery of the mixture?Type answer:
Solution
To calculate the percent recovery of the mixture, you first need to add the weight of the recovered salt and sand to get the total weight of the recovered mixture.
1.38 g (salt) + 1.32 g (sand) = 2.70 g (total recovered mixture)
Then, you divide the total weight of the recovered mixture by the original weight of the mixture and multiply by 100 to get the percent recovery.
(2.70 g / 3.02 g) * 100 = 89.4%
So, the percent recovery of the mixture is 89.4%.
Similar Questions
From a 2.921 g sample containing only iron, sand, and salt, 0.554 g of iron and 1.014 g of sand were separated and recovered.What was the percent of salt in the original sample?Type answer:
4.624 grams of a mixture of a metal, wood chips, salt and sand are separated. If 0.982 grams of metal, 0.833 grams of wood chips, 0.623 grams of salt and 0.777 grams of sand are recovered after the separation, what is the % recovery of the 4 substances? What is the % component for each of the four substances
What is the % by mass of a mixture containing 15.89 grams of salt dissolved in 677 grams of water?
Your teacher tasked you to create a salt solution, where the solute must be 23% by mass. Which of the following will help you prepare the solution?a.54 g salt; 181 g waterb.62 g salt; 450 g waterc.46 g salt; 215 g waterd.23 g salt; 100 g water
If 33.6 g of sodium chloride are dissolved in 125 g of water, what is the mass percent concentration (m/m) of NaCl in the solution?
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.