A gas mixture contains 50% helium and 50% methane by volume. What is the percent by \ weight of methane in the mixture?
Question
A gas mixture contains 50% helium and 50% methane by volume. What is the percent by \ weight of methane in the mixture?
Solution
To answer this question, we need to know the densities of helium and methane. The density of helium is about 0.1785 grams per liter and the density of methane is about 0.717 grams per liter.
Step 1: Calculate the weight of each gas in the mixture.
Assuming we have 1 liter of the mixture, we would have 0.5 liters of helium and 0.5 liters of methane.
The weight of helium = 0.5 liters * 0.1785 grams/liter = 0.08925 grams The weight of methane = 0.5 liters * 0.717 grams/liter = 0.3585 grams
Step 2: Calculate the total weight of the mixture.
The total weight = weight of helium + weight of methane = 0.08925 grams + 0.3585 grams = 0.44775 grams
Step 3: Calculate the percent by weight of methane in the mixture.
The percent by weight of methane = (weight of methane / total weight) * 100% = (0.3585 grams / 0.44775 grams) * 100% = 80.07%
So, the percent by weight of methane in the mixture is approximately 80.07%.
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