Suppose a car, moving with a constant accelaration, covers a distance of 45km in half an hour. What is the speed of the car that has attained in the given time if its initial speed is 15km/h?a.145Km/hb.165Km/hc.135Km/hd.156km/h
Question
Suppose a car, moving with a constant accelaration, covers a distance of 45km in half an hour. What is the speed of the car that has attained in the given time if its initial speed is 15km/h?a.145Km/hb.165Km/hc.135Km/hd.156km/h
Solution
The final speed of the car can be found using the equation of motion:
s = ut + 0.5at^2
where: s = displacement u = initial velocity a = acceleration t = time
Rearranging the equation to solve for a, we get:
a = (2s - 2ut) / t^2
However, we don't have enough information to find the acceleration, because the problem does not provide the final speed of the car. We would need to know either the final speed or the acceleration to solve this problem.
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