The average force necessary to stop a hammer having momentum of25 N S , in 0.05 second is I) 5N II ) 50 N III ) 500N IV) 5000 N
Question
The average force necessary to stop a hammer having momentum of25 N S , in 0.05 second is I) 5N II ) 50 N III ) 500N IV) 5000 N
Solution
The force required to stop an object can be calculated using the formula:
Force = Change in momentum / Time taken
Here, the change in momentum is 25 Ns (since the hammer is coming to a stop, its final momentum is 0, so the change in momentum is just its initial momentum), and the time taken is 0.05 seconds.
So, the force = 25 Ns / 0.05 s = 500 N.
Therefore, the correct answer is III) 500N.
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