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One insulator carries a net positive charge. Another carries a net negative charge. When the distance between them is doubled, the force between themQuestion 2Select one:a.is reduced to 1/2 the previous valueb.is reduced to 1/4 the previous valuec.stays the samed.doubles

Question

One insulator carries a net positive charge. Another carries a net negative charge. When the distance between them is doubled, the force between themQuestion 2Select one:a.is reduced to 1/2 the previous valueb.is reduced to 1/4 the previous valuec.stays the samed.doubles

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Solution

The force between two charged objects is given by Coulomb's Law, which states that the force is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

Mathematically, this is represented as F = k * q1 * q2 / r^2, where F is the force, k is Coulomb's constant, q1 and q2 are the charges, and r is the distance between the charges.

If the distance between the charges is doubled (i.e., r is replaced with 2r), then the new force F' is given by F' = k * q1 * q2 / (2r)^2 = k * q1 * q2 / 4r^2.

Therefore, the new force is 1/4 of the original force. So, the correct answer is b. The force is reduced to 1/4 the previous value.

This problem has been solved

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