A heat engine has a 75% efficiency. How much heat isabsorbed during a full cycle if the total work produced by theengine is equal to 3,6 kJ?A. 2,7 kJB. 4,8 kJC. 14,4 kJD. 0,9 kJE. 3,6 kJ
Question
A heat engine has a 75% efficiency. How much heat isabsorbed during a full cycle if the total work produced by theengine is equal to 3,6 kJ?A. 2,7 kJB. 4,8 kJC. 14,4 kJD. 0,9 kJE. 3,6 kJ
Solution
The efficiency of a heat engine is defined as the ratio of the work done by the engine to the heat absorbed by the engine. Mathematically, this is expressed as:
Efficiency = Work done / Heat absorbed
We can rearrange this equation to solve for the heat absorbed:
Heat absorbed = Work done / Efficiency
Given that the efficiency of the engine is 75% (or 0.75 when expressed as a decimal) and the work done by the engine is 3.6 kJ, we can substitute these values into the equation:
Heat absorbed = 3.6 kJ / 0.75 = 4.8 kJ
So, the heat absorbed by the engine during a full cycle is 4.8 kJ. Therefore, the correct answer is B. 4.8 kJ.
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