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Which of the following code snippets represents the correct way to delete a node from a singly linked list in C++?Group of answer choicesNode* temp = node->next; node = temp; delete temp;delete node;Node* temp = node; node = temp->next; delete temp;Node* temp = node; node->next = temp->next; delete temp;

Question

Which of the following code snippets represents the correct way to delete a node from a singly linked list in C++?Group of answer choicesNode* temp = node->next; node = temp; delete temp;delete node;Node* temp = node; node = temp->next; delete temp;Node* temp = node; node->next = temp->next; delete temp;

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Solution

The correct way to delete a node from a singly linked list in C++ is:

Node* temp = node; node = temp->next; delete temp;

Here's a step-by-step explanation:

  1. Create a temporary pointer and point it to the node you want to delete. This is done to keep a reference to the node you want to delete because once you change the 'node' pointer, you will lose the reference to the current node.

  2. Change the 'node' pointer to point to the next node in the list. This effectively removes the current node from the list because no other node is pointing to it.

  3. Delete the node using the 'delete' keyword and the temporary pointer. This frees up the memory that was allocated for the node.

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What is the correct sequence of steps to delete a node at the head of a linked list? Question 27Select one: 1. Update the head pointer to point to the next node, 2. Free the memory allocated to the head node, 3. Return the updated linked list 1. Update the next pointer of the head node to null, 2. Free the memory allocated to the head node, 3. Update the head pointer to point to the next node 1. Free the memory allocated to the head node, 2. Update the head pointer to point to the next node, 3. Return the updated linked list

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