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Question1: if the box contains six white balls and some  red  balls and if the probability of drawing a red ball from the box is twice that of a white ball then the number of red balls are*1 pointa) 3b) 6c) 24d) 12Question 2: based on the information given in question ( 1) if two more white balls added in the box , then the probability of drawing a red ball is*1 pointa) 1/2b) 3/5c)2/5d) 4/5Question 3:   If the bag contains 5 white balls , 10 blue balls and 5 green balls and if a ball is drawn at random then the probability of  not green is1 point3/41/23/51/5Question 4:   If the box contains 24 balls each of which is white , brown and yellow. the probability of choosing a white ball at random from the box  is 1/6 and  the probability of choosing a brown ball at random is 3/8, then the number of yellow ball in the box is1 point20111319

Question

Question1: if the box contains six white balls and some  red  balls and if the probability of drawing a red ball from the box is twice that of a white ball then the number of red balls are1 pointa) 3b) 6c) 24d) 12Question 2: based on the information given in question ( 1) if two more white balls added in the box , then the probability of drawing a red ball is1 pointa) 1/2b) 3/5c)2/5d) 4/5Question 3:   If the bag contains 5 white balls , 10 blue balls and 5 green balls and if a ball is drawn at random then the probability of  not green is1 point3/41/23/51/5Question 4:   If the box contains 24 balls each of which is white , brown and yellow. the probability of choosing a white ball at random from the box  is 1/6 and  the probability of choosing a brown ball at random is 3/8, then the number of yellow ball in the box is1 point20111319

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Solution

Question 1: To find the number of red balls in the box, we need to set up an equation based on the given information. Let's assume the number of red balls is "x". The probability of drawing a red ball is twice that of a white ball, so the probability of drawing a red ball is x/(x+6), and the probability of drawing a white ball is 6/(x+6). Since the probability of drawing a red ball is twice that of a white ball, we can set up the equation: x/(x+6) = 2 * (6/(x+6)). Solving this equation, we get x = 12. Therefore, the number of red balls is 12. So, the answer is d) 12.

Question 2: If two more white balls are added to the box, the total number of white balls becomes 6 + 2 = 8. The total number of balls in the box is now 8 + 12 = 20. The probability of drawing a red ball can be calculated as the number of red balls divided by the total number of balls, which is 12/20 = 3/5. So, the answer is b) 3/5.

Question 3: The total number of balls in the bag is 5 + 10 + 5 = 20. The probability of not drawing a green ball can be calculated as the number of balls that are not green divided by the total number of balls, which is (5 + 10)/20 = 15/20 = 3/4. So, the answer is 3/4.

Question 4: Let's assume the number of yellow balls in the box is "y". The total number of balls in the box is 24 + 24 + y = 48 + y. The probability of choosing a white ball at random is given as 1/6, so the number of white balls is (1/6) * (48 + y) = 8 + (y/6). The probability of choosing a brown ball at random is given as 3/8, so the number of brown balls is (3/8) * (48 + y) = 18 + (3y/8). Since the total number of balls is 48 + y, we can set up the equation: 8 + (y/6) + 18 + (3y/8) + y = 48 + y. Solving this equation, we get y = 19. Therefore, the number of yellow balls is 19. So, the answer is 19.

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