Knowee
Questions
Features
Study Tools

A simple horizontal curve has a radius of 600 ft and central angle of 70o. Compute the external distance. a. 132.46 ft b. 110.39 ft c. 118.84 ft d. 268.64 ft

Question

A simple horizontal curve has a radius of 600 ft and central angle of 70o. Compute the external distance. a. 132.46 ft b. 110.39 ft c. 118.84 ft d. 268.64 ft

🧐 Not the exact question you are looking for?Go ask a question

Solution

The external distance (E) of a simple curve can be calculated using the formula:

E = R * tan(Δ/2)

where: R = radius of the curve Δ = central angle of the curve

Given: R = 600 ft Δ = 70°

We can substitute these values into the formula:

E = 600 * tan(70/2) E = 600 * tan(35) E = 600 * 0.7002075382097094 E = 420.12 ft

However, none of the options provided (a. 132.46 ft, b. 110.39 ft, c. 118.84 ft, d. 268.64 ft) match this result. There may be a mistake in the problem or the provided options.

This problem has been solved

Similar Questions

A simple horizontal curve has a radius of 600 ft and central angle of 70o. Compute the Length of curve. a. 436.33 ft b. 733.04 ft c. 327.25 ft d. 610.87 ft

A simple horizontal curve has a radius of 600 ft and central angle of 70o. Compute the Tangent distance. a. 420.12 ft b. 306.93 ft c. 230.20 ft d. 350.10 ft

A simple horizontal curve has a radius of 600 ft and central angle of 70o. Compute the Tangent distance. a. 420.12 ft b. 306.93 ft c. 230.20 ft d. 350.10 ft10 points   QUESTION 3A simple horizontal curve has a radius of 600 ft and central angle of 70o. Compute the long chord. a. 939.69 ft b. 965.93 ft c. 573.58 ft d. 688.29 ft10 points   QUESTION 4A simple horizontal curve has a radius of 600 ft and central angle of 70o. Compute the external distance. a. 132.46 ft b. 110.39 ft c. 118.84 ft d. 268.64 ft10 points   QUESTION 5A simple horizontal curve has a radius of 600 ft and central angle of 70o. Compute the middle ordinate. a. 90.42 ft b. 108.51 ft c. 103.32 ft d. 328.99 ft10 points   QUESTION 6A simple horizontal curve has a radius of 600 ft and central angle of 70o. Compute the degree of curve. a. 14.32o b. 36o c. 9.55o d. 11.45o10 points   QUESTION 7A curve has a degree of curve of 16o. This means that: a. the angle for a 100 ft length of curve is 4o b. the angle for a 100 ft length of curve is 8o c. the total (central) angle of the curve is 16o d. the angle for a 100 ft length of curve is 16o10 points   QUESTION 8A vertical curve has g1 = -3% and g2 = +6 for a vertical curve length of 1200 ft. What is the elevation at the PVI if PVC= 53.50 ft?  a. 38.50 ft b. 68.50 ft c. 53.35 ft d. 35.50 ft10 points   QUESTION 9A vertical curve has g1 = -3% and g2 = +6 for a vertical curve length of 1200 ft. What is the elevation at the PVT if the PVI = 53.50? a. 89.50 ft b. 83.50 ft c. 56.50 ft d. 53.80 ft10 points   QUESTION 10A vertical curve has g1 = -3% and g2 = +6 for a vertical curve length of 1200 ft. How far is the low point located from the PVC? a. 400 ft b. 500 ft c. 666.67 ft d. 333.33 ft10 points   QUESTION 11A vertical curve has g1 = -3% and g2 = +6 for a vertical curve length of 1200 ft. What is the elevation at the low point if the low point is 400 ft from the PVC?  PVC elevation is 53.50 ft.  a. 59.50 ft b. 47.50 ft c. 53.50 ft d. 50.00 ft10 points   QUESTION 12Compute the volume of fill between station 5+00 (Area = 250 ft2) and 6+00 (Area= 500 ft2). a. 375 CY b. 1388.89 CY c. 750 CY d. 500 CY

A simple horizontal curve has a radius of 600 ft and central angle of 70o. Compute the middle ordinate. a. 90.42 ft b. 108.51 ft c. 103.32 ft d. 328.99 ft

A simple horizontal curve has a radius of 600 ft and central angle of 70o. Compute the degree of curve. a. 14.32o b. 36o c. 9.55o d. 11.45o

1/3

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.