The perimeter of a rectangle is 5555 feet. If the length is 1414 feet, find the width.Step 3 of 3: Finally, solve the problem by substituting in the appropriate values. (Round your answer to 2 decimal places if necessary.)
Question
The perimeter of a rectangle is 5555 feet. If the length is 1414 feet, find the width.Step 3 of 3: Finally, solve the problem by substituting in the appropriate values. (Round your answer to 2 decimal places if necessary.)
Solution
The formula for the perimeter of a rectangle is P = 2l + 2w, where P is the perimeter, l is the length, and w is the width.
Given that P = 5555 feet and l = 1414 feet, we can substitute these values into the formula:
5555 = 2(1414) + 2w
To solve for w, we first simplify the equation:
5555 = 2828 + 2w
Then, we subtract 2828 from both sides of the equation:
2727 = 2w
Finally, we divide both sides of the equation by 2 to solve for w:
w = 1363.5 feet
So, the width of the rectangle is approximately 1363.5 feet.
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